剑指 Offer 05. 替换空格

剑指 Offer 05. 替换空格

难度简单 76
请实现一个函数，把字符串 s 中的每个空格替换成”%20”。

示例 1：
输入：s = “We are happy.”
输出：“We%20are%20happy.”

class Solution {
    public String replaceSpace(String s) {
        int length = s.length();
        char[] array = new char[length * 3];//最大3倍
        int size = 0;
        for (int i = 0; i < length; i++) &#123;
            char c = s.charAt(i);
            if (c == ' ') &#123;
                array[size++] = '%';
                array[size++] = '2';
                array[size++] = '0';
            &#125; else &#123;
                array[size++] = c;
            &#125;
        &#125;
        String newStr = new String(array, 0, size);
        return newStr;
    &#125;

// 作者：LeetCode-Solution
// 链接：https://leetcode-cn.com/problems/ti-huan-kong-ge-lcof/solution/mian-shi-ti-05-ti-huan-kong-ge-by-leetcode-solutio/
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